Number to time of day conversion with datestr problem....

Hi , I have an analysed data-set that I want to present the user.This data set has analysis for a time series data, therefore i have produced aggregated data for every 15 minutes.

Now since this has to be organised, i wanted to make colums of time periods of data that i want to illustrate. I used the following lines of code:

     tp = 15/(24*60)
     kilo = 1:(24*60/15);
     l = datestr(kilo*tp,'HH:MM PM')

for first 5 points i get:::

l =

12:15 AM
12:30 AM
12:45 AM
 1:00 AM
 1:15 AM

Now the main problem is the accessibility with this new matrix l ..

%%%%%%%%%%%%%%%%
  l(1:9)

    ans =

    111  2221
  %%%%%%%%%%%%%%%%%
  l(1)

ans =

1
%%%%%%%%%%%%

instead of the above answers i want l(1) to give me '12:15 AM' and not '1'

Thank you very much for your help in advance.

Answer 1

[the cyclist]

Your output "l" is a character array, of dimension 96x8. The first row of that array can be displayed with

 >> l(1,:)

rather than

 >> l(1)

which is only the first character.

The reason that l(1:9) gave the output that you saw is the MATLAB is pulling the first 9 characters going down the first column.

You could convert that character array to a 96x1 cell array, where each row will be put into one element of the cell array, using

 >> timeCell = cellstr(l)

Then,

 >> timeCell{1}

would be the entire first row. (Note the curly brackets in that last expression, which are used to access the contents of the cell, rather than the cell itself.)

[karan]

I was being really stupid here....I got it thanks for the explanation....

For the people who are going to view in future.The following code works

tp = 15/(24*60)

kilo = 1:((24*60)/15);

l = datestr(kilo*tp,'HH:MM PM');

timeCell = cellstr(l);

y = timeCell(kilo,:)