Date Conversion
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Hi,
I have a <200x1 cell> array which consists of dates read through a text file. The dates are in the format yyyy/mm/dd hh:mm:ss:fff. I want to convert these dates into a matlab recognizable date vector which could then be later used in creating time series objects. I am not sure how to do this.
Thanks,
2 commentaires
Jan
le 19 Déc 2011
Are you sure about the colon before the fractional seconds? Usually there is a dot.
Syed Abbas
le 19 Déc 2011
Réponse acceptée
Plus de réponses (3)
Walter Roberson
le 19 Déc 2011
datenum(YourArray, 'yyyy/mm/dd HH:MM:SS.FFF')
4 commentaires
Syed Abbas
le 19 Déc 2011
Walter Roberson
le 19 Déc 2011
What does size() and class() show for the first element of your cell array, YourCell{1} ?
Are the strings absolutely consistent?
What happens if you try
cellfun(@(S) datenum(S, 'yyyy/mm/dd HH:MM:SS.FFF'), YourCell)
At the moment, it seems to me that either you do not have a cell array of strings, or else that at least one of the entries is not in the expected format.
Syed Abbas
le 19 Déc 2011
Syed Abbas
le 19 Déc 2011
Jose Jeremias Caballero
le 19 Déc 2011
Hello.
>> A={'2011/12/19 13:27:50.890';'2012/12/19 18:49:40.790'}
A =
'2011/12/19 13:27:50.890'
'2012/12/19 18:49:40.790'
>> vector=datevec(A, 'yyyy/mm/dd HH:MM:SS.FFF')
vector =
1.0e+003 *
2.0110 0.0120 0.0190 0.0130 0.0270 0.0509
2.0120 0.0120 0.0190 0.0180 0.0490 0.0408
Jan
le 19 Déc 2011
A less intelligent, but much faster method than DATENUM:
dates = {'2011/11/11 11:11:11.111'; ...
'2012/12/12 12:12:12.121'};
function Vector = myDateConversion(DateCell)
S = sprintf('%s ', DateCell{:});
D = sscanf(S, '%d/%d/%d %d:%d:%f');
Vector = transpose(reshape(D, 6, []));
On Matlab 2009a this is 5 times faster than datevec(dates, 'yyyy/mm/dd HH:MM:SS.FFF'), but datevec is much smarter and converts the '2011/32/12' correctly.
The date topic has been discussed in Mike's blog recently:
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