BITXOR OPERATION
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Hello I want to do the "bitxor" operation as shown in below code. But since bitxor takes only 2 arguments the following code gives ERROR. Please suggest a solution. Mail me at lokesh_jolly05@yahoo.co.in
L(3*(i-1)+1)=mod(bitxor(B1(3*(i-1)+1),uint64(mod((abs(X(i))-floor(abs(X(i))))*10^14,256)),256));
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Walter Roberson
le 26 Déc 2011
You have a bracket misplaced.
L(3*(i-1)+1)=mod(bitxor(B1(3*(i-1)+1),uint64(mod((abs(X(i))-floor(abs(X(i))))*10^14,256))),256);
Notice the ')' after 256 was moved to the end of the previous argument.
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