whats wrong with the code?

function fx=f(x)
for i=1:length(x)
if x(i)<0
fx(i)=x(i);
elseif x(i)==0:pi/2;
fx(i)=sin(x(i));
else
fx(i)=(sin(x(i)))
end
end
end

Réponses (2)

Thorsten
Thorsten le 7 Oct 2015
Modifié(e) : Guillaume le 7 Oct 2015

1 vote

x(i)==0:pi/2
compares x(i) to 0 and 1 (largest integer below pi/2) and gives the result in matrix of size 1x2. A matrix is considered to be true if all values are nonzero. Since x cannot be 0 and 1 at the same time, this never becomes true.
The code after else gives the same result as in the elseif before, so it does not make sense to differ between the two cases.
You don't need a for loop but you can use logical indexing to write your code, e.g.
fx(x<0) = x(x<0);
fx(x>=0 & x <= pi/2) = sin(x(x>=0 & x <= pi/2));
fx(x>pi/2) = -sin(x>pi/2);
Star Strider
Star Strider le 7 Oct 2015

0 votes

I would re-code your elseif line to:
elseif (x(i)>=0) & (x(i) <= pi/2)

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Question posée :

le 7 Oct 2015

Clôturé :

le 20 Août 2021

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