please help me with this mathematical problem
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
i have two values x and y where x=0 10 20 30 40 50 60 and y=78.54 76.19 73.65 70.85 67.72 64.26 60.19 respectively. from the above values I have to find the next values like 70 80 90 100 110... and there respective y values. please help me out.
0 commentaires
Réponses (1)
Walter Roberson
le 8 Oct 2015
The next number in the series is always 19.
Given any finite list of x and y values, there are an infinite number of functions that those y values exactly at each of the x values. At any x value not given in the list, there are then an infinite number of possibilities for y, and there is no "correct" way of determining what the corresponding y "really" is.
Therefore one might as well pick any arbitrary number as being the "real" next number in the sequence.
Consider that, after all,
polyfit([0 10 20 30 40 50 60 70 80 90], [78.54 76.19 73.65 70.85 67.72 64.26 60.19 19 19 19], 9)
should be able to come up with a perfect fit, to within the limits of floating point accuracy. Any sequence extended by any arbitrary value can still mathematically be fit by some function.
polyfit([0 10 20 30 40 50 60 70 80 90], [78.54 76.19 73.65 70.85 67.72 64.26 60.19 42 42 42], 9)
should also be able to come up with a perfect fit to within floating point accuracy
So generate any value you like and you will be right.
5 commentaires
Walter Roberson
le 8 Oct 2015
19 has been mathematically established as being correct. See http://www.whydomath.org/Reading_Room_Material/ian_stewart/9505.html
Image Analyst
le 8 Oct 2015
Bonus points if you come up with a MATLAB routine to mine random web sites to empirically come up with Benford's Law distribution.
The submissions in the File Exchange don't do that. <http://www.mathworks.com/matlabcentral/fileexchange/?utf8=%E2%9C%93&term=benford>
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!