How to solve "Index exceeds matrix dimensions" error?

My question might be simple for most of you. Basically, I would like to delete a row of a matrix where a value of the elements in columns from 2 to 7 is zero. In doing so, I run the following command.

for i=1:size(StayCell,1)

if StayCell(i,2:7)==0

StayCell(i,:)=[];

end

end

However, the error message comes up saying that "Index exceeds matrix dimensions.". I don't understand why it exceeds the dimension because I have already specified that i = 1 to the length of the matrix. Any help on this would be appreciated. Thank you.

I try also this codes but i have the same problems

for i=length(StayCell)

if(StayCell(:,2:7)==0)

StayCell(i,:)=[];

end

end

StayCell(StayCell(:,2:7)==0,:)=[];

Answer 1

[Eng. Fredius Magige]

Hi It might need to recalling as ready reduced the row, thus try this:

StayCell=StayCell for i=1:size(StayCell,1) if StayCell(i,2:7)==0 StayCell(i,:)=[]; end StayCell=(StayCell, [ ]) end

[pamela sulis]

I have the same problem... and StayCell=(StayCell, [ ]) create an error :(