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reshaping data so that I can take sum of every 3 columns

2 vues (au cours des 30 derniers jours)
Neesha
Neesha le 30 Oct 2015
Commenté : Neesha le 2 Nov 2015
Hi All,
I have a dataset something similar to following
Name Location Nickname saleCost
rest1 east Reast1 [5, 7, 9 , 2, 5, 1, 9, 11, 1]
rest4 south Rsouth4 [12, 9, 2, 3, 5, 10, 11, 4, 4]
rest3 east Reast3 [20, 2, 2, 3, 20, 30, 1, 3, 7]
rest9 west Rwest9 [1, 9, 3, 33, 22, 10, 6, 6, 8]
Note that saleCost is a dataset as well and as number of columns which are multiple of 3.
I want to add up every 3 columns so my resultant dataset is as follow
Name Location Nickname saleCost
rest1 east Reast1 [21, 8, 21]
rest4 south Rsouth4 [23, 17, 19]
rest3 east Reast3 [24, 53, 11]
rest9 west Rwest9 [13, 65, 20]
I tried using reshape() but could not use it correctly. WHat are my options?
Thanks

Réponse acceptée

Kelly Kearney
Kelly Kearney le 30 Oct 2015
When you say you have a dataset, do you mean a dataset array? I'm assuming so for the moment:
Your data:
tmp = {...
'Name' 'Location' 'Nickname' 'saleCost'
'rest1' 'east' 'Reast1' [5, 7, 9 , 2, 5, 1, 9, 11, 1]
'rest4' 'south' 'Rsouth4' [12, 9, 2, 3, 5, 10, 11, 4, 4]
'rest3' 'east' 'Reast3' [20, 2, 2, 3, 20, 30, 1, 3, 7]
'rest9' 'west' 'Rwest9' [1, 9, 3, 33, 22, 10, 6, 6, 8]};
D = cell2dataset(tmp);
Reshape:
D.saleCost = reshape(sum(reshape(D.saleCost', 3, []),1), [], size(D.saleCost,1))'
D =
Name Location Nickname saleCost
'rest1' 'east' 'Reast1' 21 8 21
'rest4' 'south' 'Rsouth4' 23 18 19
'rest3' 'east' 'Reast3' 24 53 11
'rest9' 'west' 'Rwest9' 13 65 20
Pretty much the same as Jelin's answer, but all in one command. Note that this applies to the entire array saleCost; you shouldn't need to loop over rows.
  1 commentaire
Neesha
Neesha le 2 Nov 2015
Perfect, thanks a lot! It is dataset , not an array but it does work for me...

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Plus de réponses (1)

Jacky Jo
Jacky Jo le 30 Oct 2015
Is that you want..
saleCost=[5, 7, 9 , 2, 5, 1, 9, 11, 1;...
12, 9, 2, 3, 5, 10, 11, 4, 4;...
20, 2, 2, 3, 20, 30, 1, 3, 7;...
1, 9, 3, 33, 22, 10, 6, 6, 8];
saleCost=reshape( reshape(saleCost',[],3) ,3,[]);
saleCost=reshape(sum(saleCost,1),3,[])'
  2 commentaires
Neesha
Neesha le 30 Oct 2015
Let me try what is the result. I do not want to lose context info i have as i have shown in resultant set.
Neesha
Neesha le 30 Oct 2015
It did not work, first line created all in one row with bunch of data added with default values. Also as i tried to execute second row, it ran into memory error

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