Effacer les filtres
Effacer les filtres

filter

2 vues (au cours des 30 derniers jours)
mohamed  al-asklany
mohamed al-asklany le 5 Jan 2012
in butter(1,wn) i know wn is normal frequency =(cut off/nyq.freq) in amplitude modulation what will be wn=? if carrier freq=fc and i calulat 0:.001:1 sample and message freq fm

Réponse acceptée

Rick Rosson
Rick Rosson le 6 Jan 2012
Code:
dt = 0.001; % sampling time (seconds per sample)
Fs = 1/dt; % sampling rate (samples per second)
Fnyq = Fs/2; % Nyquist frequency (hertz)
Fco = fm + bw; % Cut-off frequency (hertz)
wn = Fco/Fnyq; % Normalized cut-off (dimensionless)
Explanation:
  • dt is the sampling time (in seconds per sample)
  • Fs is the sampling rate (in samples per second)
  • Fnyq is the Nyquist frequency (in hertz)
  • Fco is the cutoff frequency (in hertz)
  • bw = bandwidth (in hertz)
  • Fc is not needed to compute wn
You should make sure that the following conditions are true:
bw << fm << fc
and
bw << fm << Fs
HTH.
Rick
  1 commentaire
mohamed  al-asklany
mohamed al-asklany le 7 Jan 2012
excellent ,now if i have a message like cos(2*pi*fm*t), and i want to build function which make frequency modulation
for this message it does not work and if it work(some times) the receiver can not be bone my problem is to how to make discriminator and how to put the message in frequency and how to see spectrum of signal and somthing else i add to am signal a noise (awgn) is this code correct
snr=10^(snr/10);
vn=var(tx)/snr; %AWGN channl
n=sqrt(vn)*randn(1,1001);
tx=tx+n;
assuming t=0:.001:1
and tx is the transmitted signal

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Plus de réponses (1)

Rick Rosson
Rick Rosson le 5 Jan 2012
Please try:
dt = 0.001;
Fs = 1/dt;
Fnyq = Fs/2;
Fco = fm + bw;
wn = Fco/Fnyq;
HTH.
  6 commentaires
Rick Rosson
Rick Rosson le 6 Jan 2012
The idea of bandwidth is that the message has a spectrum that extends across a range of frequencies centered at f = fm. You can assume that the range is [ fm-bw ... fm+bw ].
Rick Rosson
Rick Rosson le 6 Jan 2012
You should also make sure that the following conditions are true:
bw << fm
and
fm << fc

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