Scan a pattern of characters from a string
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello everyone, I have a text file from I am required to scan a pattern (string 'SSD' followed by an integer). I am trying to use the 'regexp' command for this operation. For eg. I have used the command 'fgetl' to store a line which contains the pattern I require. Could you help me with this? I want 'ord1' to find the pattern 'SSD1' from 'tline'! Thank you in advance!
tline = ## Step : SSD1
ord1 = regexp(tline,'(?<=SSDd+)','match');
0 commentaires
Réponse acceptée
Guillaume
le 6 Nov 2015
ord1 = regexp(tline, 'SSD\d+', 'match'); %if you want SSD returned as part of the match
ord1 = regexp(tline, (?<=SSD)\d+', 'match'); %if you just want the number
ord1 = regexp(tline, SSD(\d+), 'tokens', 'once'); just the number, using capture
It is '\d+' to match numbers, the slash is important. '(?<=)' tells the regex engine to look for the pattern preceding a match, but in your regexp you had nothing for the match.
Plus de réponses (1)
Image Analyst
le 6 Nov 2015
Here's an alternate way that is less cryptic than regexp():
tline = '## Step : SSD1'
ssdLocation = strfind(tline, 'SSD') % Find index of SSD
% Extract the end of the string and convert it to a number.
ord1 = str2double(tline(ssdLocation+3:end))
Voir également
Catégories
En savoir plus sur Characters and Strings dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!