Multiple element storing in a row

I have a problem about storing multiple elements in a row of an array. I have long code, but i can post short portion of it. There is a ant cell array ( it can be a multidimensional array). After some conditions, this ant{} values will change, but there is some condition multiple element will store in a row.

n=20;
for i=1:n
ant(i,:,t)= {i};
ph(i,:,t)=1;
del_ph(i,:,t)=0;
end

 ant = 

    [ 1]
    [ 2]
    [ 3]
    [ 4]
    [ 5]
    [ 6]
    [ 7]
    [ 8]
    [ 9]
    [10]
    [11]
    [12]
    [13]
    [14]
    [15]
    [16]
    [17]
    [18]
    [19]
    [20]

After calculations and some conditions, [8],[9] and [10] will move in [9], and store in this row. I did correctly move other ant{} but not reach the multiple element storing. My expected result is In this below, or like this.

ant = 
    [ 0]
    [ 1]
    [ 2]
    [ 3]
    [ 4]
    [ 5]
    [ 6]
    [ 7]
    [ 8] [ 9] [ 10]
    [11]
    [12]
    [13]
    [14]
    [15]
    [16]
    [17]
    [18]
    [19]
    [20]
    [ 0]

I tried to write a code but i think i'm bad at using arrays, so i'm stuck. Can you give me any idea? If this question isn't clear, i can post whole code and i can try explain exactly. Sorry, if i repeat same question.

Answer 1

[Stephen23]

Try concatenating those values into one numeric vector:

>> ant = num2cell(1:10)' % fake data
ant = 
    [ 1]
    [ 2]
    [ 3]
    [ 4]
    [ 5]
    [ 6]
    [ 7]
    [ 8]
    [ 9]
    [10]
>> ant{3} = [ant{3:5}]; % concatenate those values
>> ant(4:5) = [] % delete unwanted cells
ant = 
    [         1]
    [         2]
    [1x3 double]
    [         6]
    [         7]
    [         8]
    [         9]
    [        10]
>> ant{3}
ans =
     3     4     5

[Ozge Moral]

I applied to my question, it works. Thank you!