How to add a more element in an existing cell array in specific positions?

14 vues (au cours des 30 derniers jours)
Ujwal
Ujwal le 10 Nov 2015
Commenté : Ujwal le 10 Nov 2015
Hi, The problems starts like this.
I have a cell array named: FlowRate = cell(1,16);
Initially,
Flow =
[498,1] [398,3] [343,1] [840,3] [899,2] [792,2] [828,4] [440,2] [812,5] [395,4][495,5] [792,1] [876,5] [563,5] [629,1] [280,3]
After some calculation I get an array: l =[3 4 10 16], I have to make add this value [490,1] to cell position mentioned in 'l'.
So, the solution should be:
New_Flow =
[498,1] [398,3] [343,1;490,1] [840,3;490,1] [899,2] [792,2] [828,4] [440,2] [812,5] [395,4;490,1][495,5] [792,1] [876,5] [563,5] [629,1] [280,3;490,1]
I would be grateful to get your support. Than You.

Réponse acceptée

Stephen23
Stephen23 le 10 Nov 2015
Modifié(e) : Stephen23 le 10 Nov 2015
Note that l is not a good variable name, as it is too easy to confuse for other characters.
Try this:
>> C = {[498,1],[398,3],[343,1],[840,3],[899,2],[792,2],[828,4],[440,2],[812,5],[395,4],[495,5],[792,1],[876,5],[563,5],[629,1],[280,3]};
>> idx = [3,4,10,16];
>> new = [490,1];
>> C(idx) = cellfun(@(v)[v;new],C(idx),'UniformOutput',false);
>> C{:}
ans =
498 1
ans =
398 3
ans =
343 1
490 1
ans =
840 3
490 1
ans =
899 2
ans =
792 2
ans =
828 4
... etc

Plus de réponses (1)

Walter Roberson
Walter Roberson le 10 Nov 2015
what_to_add = [490,1];
for K = I
New_Flow{K} = [New_Flow{K}, what_to_add];
end
  1 commentaire
Ujwal
Ujwal le 10 Nov 2015
absolutely very short answer. I am sorry for not knowing this simple text too.

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