How to keep count in a nested for loop?

Hi, I'm sure the answer is simple but I just can't figure it out. Let's say I have this code:
for i=1:3
for j=1:3
count=??;
end
end
count
I want the result to be count=[1 2 3 4 5 6 7 8 9]
Thanks

Réponses (2)

the cyclist
the cyclist le 17 Nov 2015
There are many ways to do this. Here is one.
c = 0;
for i=1:3
for j=1:3
c=c+1;
end
end
count = 1:c

1 commentaire

baby
baby le 26 Sep 2021
Modifié(e) : baby le 26 Sep 2021
you saved my life.

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the cyclist
the cyclist le 17 Nov 2015
Here is one way:
irange = 1:3;
jrange = 1:3;
for i=irange
for j=jrange
end
end
count = 1:(numel(irange)*numel(jrange));

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Question posée :

le 17 Nov 2015

Modifié(e) :

le 26 Sep 2021

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