Effacer les filtres
Effacer les filtres

Parfor loop slicing question.

2 vues (au cours des 30 derniers jours)
andrew joros
andrew joros le 9 Jan 2012
Can someone tell me how to slice the array "data" that is within the parfor loop in the code below?:
parfor i=1:32 %fprintf('Now on year %d\n',i);
% data((1+(366*(i-1)):366*i),1)=1979+(i-1);
% data((1+(366*(i-1)):366*i),2)=1:366;
data((1+(366*(i-1)):366*i),3)=squeeze(motemp.TMIN(loni,lati,:,i));
data((1+(366*(i-1)):366*i),4)=squeeze(motemp.TMAX(loni,lati,:,i));
data((1+(366*(i-1)):366*i),5)=squeeze(mowind.WIND(loni,lati,:,i));
data((1+(366*(i-1)):366*i),6)=squeeze(moshum.DATA(loni,lati,:,i));
data((1+(366*(i-1)):366*i),7)=squeeze(morad.RADIATION(loni,lati,:,i));
end
FYI The array 'data' is 11712x15.
If you want to see the full code go here: http://pastebin.com/H3HEwAwR
Thanks and much appreciated.
I'm willing to paypal someone a little cash if they can help me out here.
  4 commentaires
Michael
Michael le 10 Jan 2012
Ah, that is tricky. The result would be 103936 .mat files? I would suggest running profiler to find where most time is spent (perhaps for 5-10 lat/long points) because I have a bad feeling the majority of it will be spent writing the large files to storage which would be considerably slower than any matrix reshaping done by the CPU (and would also probably not benefit from parallel architecture within the CPU).
andrew joros
andrew joros le 10 Jan 2012
Yes I will be making ~104k .mat files. I am thinking parfor wont be any fast than a regular for-loop. Right?

Connectez-vous pour commenter.

Réponses (1)

Edric Ellis
Edric Ellis le 10 Jan 2012
Looking at your complete code, I would strongly recommend that you try to apply PARFOR to the outermost loop that gives you sufficient parallelism (i.e. has at least as many iterations as you have workers). This is generally the most efficient. It looks to me like either of the 2 outermost loops would be reasonable candidates.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by