Calling a custom function in fittype

10 vues (au cours des 30 derniers jours)
David
David le 27 Nov 2015
Commenté : Oisín Conway le 7 Oct 2022
Hi,
I am attempting to create a custom fit, which itself calls a simple function.
In a separate .m file I define a function for finding the full width at half maximum of a curve ("Y"):
function[F05] = FWHMf(x,Y)
[~,b] = min(abs(Y-0.5));
F05 = 2*abs(x(b));
I then call this function in my main .m file thus:
F3 = @(w,x,q,S) FWHMf(x,exp(-x.^2./(q+w^2)));
CF3 = fittype(F3,'coefficients','w','independent',{'x','q'},'dependent','S');
Where, I have measured "S" as function of "q", and I wish to find the parameter "w" using the fit.
This code produces an error:
"Custom equations must produce an output vector, matrix, or array that is the same size and shape as the input data. This custom equation fails to meet that requirement"
when run in Matlab version 2014b.
I know I must be doing something wrong here, perhaps in my entire approach to the problem. Any suggestions would be greatly appreciated.
Cheers,
David

Réponses (1)

David
David le 30 Nov 2015
In case it simplifies the situation at all, I have rewrote the FWHMf function to:
function[F05] = FWHMf(x,Y)
F05 = 2*sqrt(log(2))*sum(x.^2.*Y)/sum(Y);
I've tried a few different things but still can't get the code to define the fittype without throwing up an error.
  1 commentaire
Oisín Conway
Oisín Conway le 7 Oct 2022
Hello @David, was this solved in the end?

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