Eliminate of empty matrix on cell structure.

Hi everbody.

I have 1*1724 cell structure and i want to find which cells are not empty matrix.

for l=1:1:1724
    if buyuk_elemanlar{1,l}==[];
        clear buyuk_elemanlar{1,l}
elseif 
   ???

      end
  end

I don'nt know how type matlab code after the "elseif"?

Answer 1

[Image Analyst]

Try it like this:

if isempty(buyuk_elemanlar{1,l})
     % Cell is empty....

[Volkan Yangin]

Thanks a lot Image Analyst, your solution is very helpful for me now. :-)

Answer 2

[Jan]

Use isempty instead of | == []|. clear is not useful to remove a single element. Do not remove elements of the cell inside the loop. Because then the loop index does not match the cell index anymore.

Different solutions:

m = false(1, 1724);
for k = 1:1724
  if isempty(buyuk_elemanlar{1, k})
     m(k) = true;
  end
end
buyuk_elemanlar(m) = [];

Or:

m = false(1, 1724);
for k = 1:1724
  m(k) = isempty(buyuk_elemanlar{1, k})
end
buyuk_elemanlar(m) = [];

Or:

m = cellfun('isempty', buyuk_elemanlar);
buyuk_elemanlar(m) = [];

The meaning of the "elseif ???" cannot be guessed. What should happen when the cell is not empty?

[Volkan Yangin]

Thank you. Jan Simon. When i used elseif function, it is not useful for solve this problem, too. This only changes the for ex. 1x24cell to "l" Now i will use your solution with not using elseif and clear functions and i think, problem will be resolved by your codes. Thanks a lot again. :-)