how to use if else of for loops to manipulate matrices

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selassie ngara
selassie ngara le 1 Déc 2015
Commenté : selassie ngara le 1 Déc 2015
i have a two column matrix (many rows) and i want to read column 1 values corresponding with certain values in column 2 under a certain condition that only column 2 can be tested. say column 2 must be over 3.4 and i want times corresponding(column1)

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Thorsten
Thorsten le 1 Déc 2015
Modifié(e) : Thorsten le 1 Déc 2015
To get all values from column 1 of X, where column 2 is > 3.4:
x = X(X(:,2) > 3.4, 1);
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selassie ngara
selassie ngara le 1 Déc 2015
thanks, it makes sense but it takes a whyle to get your head arnd it

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Eng. Fredius Magige
Eng. Fredius Magige le 1 Déc 2015
For can assist you in searching each index in sequence order through find function as long you know/specify appropriate condition to be determine by if else. Note that find function return to you raw and column, in many case column will 1 always.

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