Hello, Suppose that I have a matrix a= [1 3; 4 2], I convert this matrix to binary format using this code:
a=magic(2)
y=dec2bin(a,8)
e=str2num(y(:))';
The result is :
y =
00000001
00000100
00000011
00000010
e =
Columns 1 through 17
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Columns 18 through 32
0 0 0 0 1 0 0 0 0 1 1 1 0 1 0
Now when I want to get back my original matrix I inverse the function : s=num2str(e(:))'; r=bin2dec(s)
The results I got is:
r =
1082
What can I do to get the orignal matrix? not a number Thank you in advance

 Réponse acceptée

Thorsten
Thorsten le 2 Déc 2015
aback = reshape(bin2dec(num2str(reshape(e, 4, []))), 2, 2);

Plus de réponses (0)

Catégories

En savoir plus sur MATLAB dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by