Effacer les filtres
Effacer les filtres

Error using - Matrix dimensions must agree. Error in WDO_SG_Code_PL_test1m (line 322) a2=aa-a1; i got the error my code segment is below can any one help me why this error came?

1 vue (au cours des 30 derniers jours)
sorry i can not paste the whole code this is a segment of code _______________________________________________________________
u(hour)=hour;
Clothesdryer(hour)=power_pattern(hour,1);
a1=find(Clothesdryer);
Dish_washer(hour)=power_pattern(hour,2);
b1=find(Dish_washer);
Washing_Machine(hour)=power_pattern(hour,3);
c1=find(Washing_Machine);
oven(hour)=power_pattern(hour,4);
d1=find(oven);
iron(hour)=power_pattern(hour,5);
e1=find(iron);
Refrigerator(hour)=power_pattern(hour,6);
f1=find(Refrigerator);
Lightening(hour)=power_pattern(hour,7);
g1=find(Lightening);
Vaccume_cleaner(hour)=power_pattern(hour,8);
h1=find(Vaccume_cleaner);
PoolPump(hour)=power_pattern(hour,9);
i1=find(PoolPump);
EWH(hour)=power_pattern(hour,10);
j1=find(EWH);
Hairdryer(hour)=power_pattern(hour,11);
k1=find(Hairdryer);
AC(hour)=power_pattern(hour,12);
L1=find(AC);
%------------------------------------------% % xlswrite(filename1,WHeate)
end
Indexx
a2=aa-a1;
% a3=sum((a2)/9);
b2=bb-b1;
c2=cc-c1;
d2=dd-d1;
e2=ee-e1;
f2=ff-f1;
g2=gg-g1;
h2=hh-h1;
i2=ii-i1;
j2=jj-j1;
k2=kk-k1;
L2=LL-L1;
BAR(2,1)=sum_E_Cost_SS;
  3 commentaires
Zafar Iqbal
Zafar Iqbal le 2 Déc 2015
>> size(aa)
ans =
1 9
>> size(a1)
ans =
1 3
>> size(a2) Undefined function or variable 'a2'. thanks torsten,i do this can u help me more as 1 9-1 3 should be ok
Torsten
Torsten le 2 Déc 2015
But how to subtract an 1x3 array from an 1x9 array ? Impossible.
Best wishes
Torsten.

Connectez-vous pour commenter.

Réponses (1)

Thorsten
Thorsten le 2 Déc 2015
Check the sizes by adding
whos aa
whos a1
before the a2=aa-a1; line.
aa and a1 must have the same size, otherwise you get the error.
  4 commentaires
Thorsten
Thorsten le 3 Déc 2015
Modifié(e) : Thorsten le 3 Déc 2015
Zafar, you want to subtract 3 values from 9 values. That's not defined. One way to handle this would be
len = min([numel(aa) numel(a1]);
a2 = aa(1:len) - a1(1:len);
But I have no idea whether this makes sense in your code.
Maybe something needs to be fixed in the computation of aa and a1 such that they cannot have different sizes.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by