why imerode and imdilate make matlab stopped every time ?

5 vues (au cours des 30 derniers jours)
alaa adel
alaa adel le 8 Déc 2015
Commenté : Walter Roberson le 10 Déc 2015
after write imerode function
i=imread('\cameraman.jpg');
B=im2bw(1,0.3);
K3=ones(3);
K5=ones(5);
K7=ones(7);
K9=ones(9);
B3=imerode(B,K3);
B5=imerode(B,K5);
B7=imerode(B,K7);
B9=imerode(B,K9);
imshow(B)
figure, imshow(B3), title('by 3');
figure, imshow(B5), title('by 5');
figure, imshow(B7), title('by 7');
figure, imshow(B9), title('by 9');
matlab stop and popup msg with matlab must be debug ?
what can i do ?
function imdilate show msg matlab has encountered an internal problem and need to close .
so how solve this problem ?
  2 commentaires
Walter Roberson
Walter Roberson le 8 Déc 2015
Does your MATLAB also stop working as soon as you draw any graphics? For example, does plot(3,5) cause problems?
Amith Kamath
Amith Kamath le 8 Déc 2015
FYI: The crash can be observed by doing this:
imerode(true, ones(3,3));
There is no crash observed for other strel sizes.

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Réponse acceptée

Amith Kamath
Amith Kamath le 8 Déc 2015
Alaa:
You've probably found a bug in imerode. However, I believe you really meant to do this instead:
B = im2bw(i, 0.3); % in this case, B is indeed the 256x256 matrix.
rather than
B = im2bw(1,0.3); % in this case, B is a scalar logical value of 1.
Doing so will not make MATLAB crash, but provide you the results you were originally looking for.
Hope this helps!
  2 commentaires
alaa adel
alaa adel le 9 Déc 2015
Modifié(e) : Walter Roberson le 10 Déc 2015
thank you for your help
this
B= im2bw(i);
solve my problem as not make MATLAB crash
but i don't know the reason
Walter Roberson
Walter Roberson le 10 Déc 2015
This is one of the reasons to avoid using i as a variable name.

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