vectorize this structure call?

6 vues (au cours des 30 derniers jours)
Tom
Tom le 13 Jan 2012
I have failed at trying to vectorize this. Would love some help!
Thanks!
for l = 1:length(tree.Steps.Step)
wavelength(l) = tree.Steps.Step(l).ATTRIBUTE.Scanning_parameter_value;
for m = 1:length(tree.Steps.Step(l).Far_field.Order)
order_num(m,l) = tree.Steps.Step(l).Far_field.Order(m).ATTRIBUTE.Order_number;
efficiency(m,l) = tree.Steps.Step(l).Far_field.Order(m).ATTRIBUTE.Efficiency;
end
end
  1 commentaire
Charlie
Charlie le 28 Avr 2013
Did you have any success in vectorizing the outside loop?
I am trying to do a similar operation. I am trying the equivalent of cell2mat(tree.Steps.Step) which seems to successfully vectorise these. I am confused why I can put a structure into a matrix though.

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Réponses (1)

Walter Roberson
Walter Roberson le 13 Jan 2012
Uggh, but yes it can be done. The following code is partly tested.
for l = 1:length(tree.Steps.Step)
wavelength(l) = tree.Steps.Step(l).ATTRIBUTE.Scanning_parameter_value;
temp1 = cell2mat(struct2cell(tree.Steps.Step(l).Far_field.Order));
temp2 = cell2mat(struct2cell([temp1.ATTRIBUTE]));
order_num(:,l) = [temp2.Order_number];
efficiency(:,l) = [temp2.Efficiency];
end
Possibly there are more efficient ways to handle this using structfun().
  2 commentaires
Tom
Tom le 17 Jan 2012
Thank you! This does remove the inner loop. Any thoughts on removing the outer loop?
Walter Roberson
Walter Roberson le 17 Jan 2012
I am not sure at the moment that removing the outer loop is possible, except through techniques such as cellfun(). I have not worked through it.

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