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The way MATLAB executes a code

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Richard
Richard le 17 Jan 2012
Just wondering... suppose I have a code like
a = 1+2+3;
b = 1+3+5;
c = a+b;
fprintf('%2d',c)
What is MATLAB actually doing? Does it evaluate a before reading the line of code for b, or does it skip over the individual calculations until it reaches the print command which asks for a and b to be evaluated?
In other words, if the code is such that
a = 1+2+3;
b = 1+3+5;
fprintf('%2d',b)
would a get evaluated too and stored somewhere?
Thank you.

Réponse acceptée

the cyclist
the cyclist le 17 Jan 2012
MATLAB is a procedural language. It will calculate and store a and b, regardless of later lines of code "needing" them. In the MATLAB editor, you will see a warning that those variables may be unused.
  1 commentaire
Richard
Richard le 17 Jan 2012
Thanks, the cyclist! :-)

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