HELP PLEASE!! How do I print matlab "1:5 multiply increases each line"

1 vue (au cours des 30 derniers jours)
Ken kaneki
Ken kaneki le 18 Jan 2016
Modifié(e) : Stephen23 le 18 Jan 2016
This is my code
clc
fprintf (' SGD USD GBP EURO \n')
for (x= 1 : 5)
USD = 0.69 *2;
GBP = 0.49 *2;
EURO = 0.64 *2;
fprintf (' \n %d %.2f %.2f %.2f ' ,SGD ,USD ,GBP ,EURO);
end
My results
SGD USD GBP EURO
1 1.38 0.98 1.28
1 1.38 0.98 1.28
1 1.38 0.98 1.28
1 1.38 0.98 1.28
1 1.38 0.98 1.28 >>
I want the 2nd line to multiple by two, the thrid line to multiple by three... so on and so fourth...

Réponse acceptée

Stephen23
Stephen23 le 18 Jan 2016
Modifié(e) : Stephen23 le 18 Jan 2016
Without any loops, using vectorized code. Note that you can simply add new currencies to the arrays and it will work perfectly (i.e. changing the code itself is not required):
% the arrays:
name = {'SGD','USD','GBP','EURO'};
xchg = [ 1, 0.69, 0.49, 0.64];
mult = [1:5,10,20]; % multiples
% the code:
fprintf('%8s',name{:})
fprintf('\n')
fmt = repmat('%8.2f',1,numel(name));
fprintf([fmt,'\n'],xchg(:)*mult)
prints this:
SGD USD GBP EURO
1.00 0.69 0.49 0.64
2.00 1.38 0.98 1.28
3.00 2.07 1.47 1.92
4.00 2.76 1.96 2.56
5.00 3.45 2.45 3.20
10.00 6.90 4.90 6.40
20.00 13.80 9.80 12.80
  3 commentaires
Stephen23
Stephen23 le 18 Jan 2016
Modifié(e) : Stephen23 le 18 Jan 2016
My pleasure. Here are a few tips to understand how my solution works:
  1. fprintf keeps repeating its format until it runs out of values to work with: this means that fprintf('%f,',1:3) prints '1,2,3,'.
  2. The minimum total width of the output can be set: fprintf('%4f',1) prints '___1' (three spaces are indicated here by three underscores).
  3. The product xchg(:)*mult calculates all values at once in a matrix. Try it in your command window!
Now you should be able to understand how it works. Of course the fprintf documentation explains how it behaves, that is where I learned how to do these kind of things.
Ken kaneki
Ken kaneki le 18 Jan 2016
Thanks Stephen, i'm slowly digesting it hahaha! I guess it's gonna take awhile...

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Plus de réponses (1)

C.J. Harris
C.J. Harris le 18 Jan 2016
Do you mean like this?
clc
fprintf(' SGD USD GBP EURO \n')
for x= 1 : 5
USD = 0.69 * 2 * x;
GBP = 0.49 * 2 * x;
EURO = 0.64 * 2 * x;
SGD = x;
fprintf (' \n %d %.2f %.2f %.2f ' ,SGD ,USD ,GBP ,EURO);
end
Result:
SGD USD GBP EURO
1 1.38 0.98 1.28
2 2.76 1.96 2.56
3 4.14 2.94 3.84
4 5.52 3.92 5.12
5 6.90 4.90 6.40
  1 commentaire
Ken kaneki
Ken kaneki le 18 Jan 2016
Thank you guys for your time and offered help to me, really really appreciated. The mistake i made was I didn't add the * x; !!

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