How improve for cycle with sequential variables name and time evaluate ?

3 vues (au cours des 30 derniers jours)
Stefano Alberti
Stefano Alberti le 11 Fév 2016
Modifié(e) : Stephen23 le 19 Juin 2019
I've this for cycle:
for k =1:3 %numel(D)
fid = fopen(fullfile(D(k).name), 'rt');
filename = D(k).name ;
a=filename(11:end);
b=regexp(a,'__','split');
out1=cellfun(@(x) datestr(datenum(x(1:10),'yyyy_mm_dd'),'yyyy/mm/dd'),b,'un',0);
out2=cellfun(@(x) datestr(datenum(x(12:end),'HH_MM'),'HH:MM'),b,'un',0);
out=[out1' out2'];
clearvars out1 out2;
fclose(fid);
end
I want to assign a cumulative name at the variables 'out' like 'out-1', 'out-2', ... for each for cycle. I try do that with this code:
t1 = cell(numel(D), 1);
t2 = cell(numel(D), 1);
for j=1:numel(D);
t1{j} = sprintf('TimeStart %u', j);
t2{j} = sprintf('TimeFinish %u',j);
end
But I don't now how put this code in the for cycle.
I need to evaluate che difference between two dates & times, and for do that I use this code:
prova = [out{1,1}, ' ', out{1,2}];
prova2 = [out{2,1}, ' ', out{2,2}];
format shortg;
t1 = datevec(prova,'yyyy/mm/dd HH:MM');
t2 = datevec(prova2,'yyyy/mm/dd HH:MM');
e=etime(t2, t1)
I need to do that with a iterative cycle, for each cell and create a file with the column of results.
Thanks in advance.
Stefano
  1 commentaire
Stephen23
Stephen23 le 11 Fév 2016
Read the answers, and then use a cell array or structure.

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Réponse acceptée

Stephen23
Stephen23 le 11 Fév 2016
Modifié(e) : Stephen23 le 19 Juin 2019
  7 commentaires
Stephen23
Stephen23 le 12 Fév 2016
Modifié(e) : Stephen23 le 12 Fév 2016
Don't use my code inside the loop. Just give it a cell array of the filenames:
C = {D.name};
% my code here
for k = 1:numel(D)
out(k) % the time difference
% your code here
end
and it will work. Putting my code before the loop will be faster and neater, and within the loop you can access the elements of out using indexing:
out(k)
The reason your code does not work is because you misunderstand what
D.name
does. It is explained in the documentation for non-scalar structures. In short this:
D.name
D(1).name, D(2).name, D(3).name, ...,D(end).name
However it does not create a cell array of strings! So when you use it as an input to regexp it is equivalent to lots of separate inputs:
regexp(D(1).name, D(2).name, ...,, D(end).name, ...)
as multiple inputs, exactly as the documentation describes. Those extra inputs are interpreted as optional arguments, but do not match any options and cause an error. If you want to have those strings in a cell array, then put your list into a cell array:
{D.name}
to make a cell array of strings. It is easy to check this behavior yourself:
>> S = struct('name',{'A','B','C'});
>> S.name % comma-separated list = separate variables!!
ans =
A
ans =
B
ans =
C
>> {S.name} % put them in a cell array
ans =
'A' 'B' 'C'
Stefano Alberti
Stefano Alberti le 12 Fév 2016
Thank you very much Stephen!

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 11 Fév 2016
  2 commentaires
Stefano Alberti
Stefano Alberti le 11 Fév 2016
Thanks Walter, I've tried to read that but I didn't found the solution at my problem.
Walter Roberson
Walter Roberson le 11 Fév 2016
Modifié(e) : Stephen23 le 11 Fév 2016
"I want to assign a cumulative name at the variables 'out' like 'out-1', 'out-2'"
Don't do that. Indices have no place in variable names. If you want to index, use a cell array or struct array.

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