Effacer les filtres
Effacer les filtres

what am I doing wrong here?

1 vue (au cours des 30 derniers jours)
Jonathan Trencheny
Jonathan Trencheny le 15 Fév 2016
function a = problem4c (m)
m=4;
a = [1:m; 2:m; 3:m; 4:m; 5:m];
x = mean(a);
avg = mean(x);
I keep getting, in red letters:
Error using vertcat
Dimensions of matrices being concatenated are not consistent.
Error in problem4c (line 3)
a = [1:m; 2:m; 3:m; 4:m; 5:m];
Error in run (line 96)
evalin('caller', [script ';']);

Réponses (2)

Image Analyst
Image Analyst le 15 Fév 2016
The rows don't have all the same number of columns. Instead of putting the vectors into different rows with semicolons, put them into the same row with commas:
a = [1:m, 2:m, 3:m, 4:m, 5:m];
  2 commentaires
Jonathan Trencheny
Jonathan Trencheny le 15 Fév 2016
I see, and that makes sense, however what would we do if we need to keep it a matrix?
Walter Roberson
Walter Roberson le 15 Fév 2016
a = {1:m; 2:m; 3:m; 4:m; 5:m};
x = cellfun(@mean, a);

Connectez-vous pour commenter.


Star Strider
Star Strider le 15 Fév 2016
I don’t know what the problem statement is, but from what I’ve seen, one option might be:
m = 4;
v = m:-1:0;
c = cumsum(0:m);
s = sum(1:m) - c;
avg = s./v
avg =
2.5 3 3.5 4 NaN

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by