a = [30 30 30 10 10 0 0 10 20 20];
a1 = unique(a);
a2 = perms([a1,fliplr(a1)]);
p1 = [a2 , fliplr(a2),a2 , fliplr(a2), a2];
p2 = p1 (:, 1:length(a));
ppp = unique(p2,'rows');
pp = permute(ppp, [3 2 1]);
if unique(a) is less than 2 times then i have to eliminate rows in ppp or pp.

 Réponse acceptée

Walter Roberson
Walter Roberson le 20 Fév 2016

0 votes

threshold = 2;
ppp( sum(ismember(ppp, a1), 2) < threshold, :) = [];

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