how to fill the value of "1" where ever you want in an array.

hello guys i want to fill "1"s in an array where ever i want, for example

for m = 1:64
    t = ones(1,((64/4^level))) 
   if level = 1, then the output should be getting sequence of 16 "ones" filled from 1 to 16, remaining should be zeroes.which is happeneing using my code.
   if level = 2, then the output should be getting sequence of 4 "ones" repeated 4 times in the positions from   1, 17,33,49.
end

im using ones(1,((64/4^level))) operation,,,, but for level 2, repetition of 1's sequence in the positions 1,17,33,49 is not happening, im a beginner kindly help me.

[the cyclist]

What output do you want for level=3 and level=4?

[Jan]

Please post the original code. "Is not happening" together with only a rough description of the code does not reveal what's going on.

[Sandeep Kumar]

sure sir, the original code is

N= 16; level =1;

 for m = 1:N
 t = ones(1,((N/4^level))) 
 end
%%for a 64 bit only level 1 and level 2 will be present

it was designed by me, its not generic.

k my main aim is if

N= 16 there will only level 1

N= 64 there will only level 1 and level 2

N= 256 there will be level 1 and level 2 and level 3. . .

if N= 16,(level = 1) it should be having 4 ones in the starting sequence, %%working using my code

if N= 64, for level 1, it should have 16 ones from the starting sequence %%working using my code

if N= 64, for level 2, it should be having 4 ones starting in the positions from 1,17,33,49, its like this 1)1,2)1,3)1,4)1,5)0,6)0......17)1,18)1,19)1,20)1,21)0....33)1,34)1..

if N=256, for level 1, it should have 64 ones from the starting sequence %%working using my code

if N= 256, for level 2, it should be having 16 ones starting in the positions from 1,65,129,193 its like this 1)1,2)1,3)1,4)1......,17)0,18)0,21)0....65)1,66)1,67)1....129)1,130)1 .....193)1,194)1

if N=256, for level 3, it should have 4 ones from the starting sequence 1)1,2)1,3)1,4)1,5)0,6)0......17)1,18)1,19)1,20)1,21)0....33)1,34)1.. ..241)1,242)1,243)1,244)1,245)0 thats it., i hope i gave my whole aim of the project.

[Image Analyst]

Is this homework? Can you try to think up the formula for computing "numberOfOnes" from "N" and "level", like I did in my answer below?

Answer 1

[Image Analyst]

I just got a copy of the Mind Reading Toolbox, though it's just valid for this weekend. What I got out was:

% Initialize an output array
output = zeros(1, 64);
% Define level: 1 or 2
level = 2;
% Define the number of elements to assign: 16 or 4.
numElementsToAssign = 16 / level^2
% Define the increment between index numbers: 1 or 16.
increment = 15*level - 14
% Generate the indexes
indexes = 1 : increment : length(output)
% Finally, assign the outputs.
output(indexes(1:numElementsToAssign)) = 1

I gives what you asked for and, I think, gives you what you want, at least for levels 1 and 2 like you asked for. No guarantees if you want something weird for levels 3, 4, etc.

Answer 2

[dpb]

_"repetition of 1's sequence in the positions 1,17,33,49..."

Use colon indexing--

t(1:16:LENGTH)=1;

where LENGTH is the maximum length of the vector wanted. The '1' and '16' can be computed and any relationship desired, of course.

I suggest reading and working thru the examples in the "Getting Started" documentation section to get a quick tutorial on Matlab syntax and such basic operations as the quickest way to get over the initial startup problem.

[Sandeep Kumar]

thanku for the answer sir , i tried it, it is working in a way, what i exactly meant is "repetition of 1's sequence in the positions 1,17,33,49..." its like this 1)1, 2)1, 3)1, 4)1, 5)0, 6)0 ...... 17)1, 18)1, 19)1, 20)1, 21)0.... 33)1,34)1.. upto 64 for N=64,level=2.