tab delimited text file from matlab

clear all
    a = rand(131400,12);
    DateTime=datestr(datenum('2011-01-01 00:01','yyyy-mm-dd HH:MM'):4/(60*24):...
        datenum('2011-12-31 23:57','yyyy-mm-dd HH:MM'),...
        'yyyy-mm-dd HH:MM');
    DateTime=cellstr(DateTime);
    header={'DateTime','temp1','temp2','temp4','temp7','temp10',...
        'temp13','temp16','temp19','temp22','temp25','temp30','temp35'};

I'm trying to convert the outputs into one variable (called 'Data'), i.e. have header as the first row (1,:), 'DateTime' starting from row 2 (2:end,1) and running through each row, and finally having 'a' as the data (2:end,2:end) if that makes sense. So, 'DateTime' and 'header' are used as the heading for the rows and column respectively. Following this I need to save this into a tab delimited text file.

I hope I've been clear in expressing what I'm attempting.

[Jan]

You forgot to ask a question.

Answer 1

[Jan]

Do you look for a function to write the tab-separated file?

a = rand(131400,12);
DateTime = datestr(datenum('2011-01-01 00:01','yyyy-mm-dd HH:MM'):4/(60*24):...
      datenum('2011-12-31 23:57','yyyy-mm-dd HH:MM'),...
      'yyyy-mm-dd HH:MM');
DateTime = cellstr(DateTime);  % I assume it is a cell string already?!
header = {'DateTime','temp1','temp2','temp4','temp7','temp10',...
      'temp13','temp16','temp19','temp22','temp25','temp30','temp35'};

FID = fopen(FileName, 'w');
if FID < 0, error('Cannot open file'); end
for i = 1:numel(DateTime)
  fprintf('%s\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t\n', ...
          DateTime{i}, a(i, :));
end
fclose(FID);

[Richard]

Although you didn't understand what I was asking, what you have shown works perfectly. thanks

[wenwu xiu]

Good response, but it seems that the header line is not inserted in the new File. How to do that, any ideas? Thx