Effacer les filtres
Effacer les filtres

Transposing 3 D matrix using permute - how does permute work?

38 vues (au cours des 30 derniers jours)
Ali
Ali le 24 Jan 2012
Commenté : Javed mohd le 7 Mar 2018
Ok. So I see how to transpose all the "2D slices" of a 3D matrix on other answers (permute(A, [2 1 3])).
But what does the order vector mean? The 2 means what? The second row, column? Anyone who can explain this, I appreciate it.
Thanks
  2 commentaires
Andrew Newell
Andrew Newell le 24 Jan 2012
Have you tried "doc permute" yet?
Javed mohd
Javed mohd le 7 Mar 2018
Hi, Order vector [1:first dim(row) 2:second dim(col) 3:third dim(Z)] so if you want to transpose rows and columns keeping the same Z, your vector would be [2 1 3]

Connectez-vous pour commenter.

Réponse acceptée

Walter Roberson
Walter Roberson le 24 Jan 2012
It is the dimension number. In [2 1 3] it means that the second dimension of the original should become the first dimension of the new array, and the first dimension of the original should become the second dimension of the new array, and the third dimension of the original should stay where it is.

Plus de réponses (2)

James Tursa
James Tursa le 25 Jan 2012
Another way to do 2D slice transposing of an nD Array:
mtimesx(1,A,'t')
You can find mtimesx on the FEX here:
href=""<http://www.mathworks.com/matlabcentral/fileexchange/25977-mtimesx-fast-matrix-multiply-with-multi-dimensional-support</a>>

Ali
Ali le 24 Jan 2012
Hello all,
Yeah.. I checked the docs before posted the message. I got it now. Thanks.
I think the docs could be improved a little bit, like an example.
A = [1 2; 3 4]
NewA = permute(A, [2,1,3])
=>
A(1,1) => NewA(1,1)
A(1,2) => NewA(2,1)
A(2,1) => NewA(1,2)
A(2,2) => NewA(2,2)
NewA = [1 3; 2 4]
  2 commentaires
Walter Roberson
Walter Roberson le 24 Jan 2012
The third dimension has length 1, and it is left where it is, so the third dimension is 1 afterwards. Trailing 1's from the third dimension onward are not explicitly shown in MATLAB. An array which is 2x2 is also 2x2x1x1x1x1x1 but it would not serve any useful purpose to explicitly display the 250-some-odd trailing subscripts that are all exactly "1".
Andrew Newell
Andrew Newell le 24 Jan 2012
Each doc page has an option for feedback at the bottom. If you answer "No" to "Was this topic helpful?", you'll get a web form to fill out.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Matrices and Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by