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I have a list of triangles of the mesh and point cloud. the question is :how to determine each point belongs to a triangle

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I have a list of triangles of the mesh and point cloud. the question is :how to determine each point belongs to a triangle
  5 commentaires
amina lk
amina lk le 28 Fév 2016
thank you i resolt my prob of projection by this file joint
amina lk
amina lk le 28 Fév 2016
thank you i resolt my prob of projection by this file joint

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Roger Stafford
Roger Stafford le 26 Fév 2016
Let the points (x1,y1), (x2,y2), and (x3,y3) be the three vertices of a triangle, and let (x,y) be some arbitrary point. Define:
c1 = (x2-x1)*(y3-y1)-(x3-x1)*(y2-y1);
p1 = (x2-x) *(y3-y) -(x3-x) *(y2-y) ;
c2 = (x3-x2)*(y1-y2)-(x1-x2)*(y3-y2);
p2 = (x3-x) *(y1-y) -(x1-x) *(y3-y) ;
c3 = (x1-x3)*(y2-y3)-(x2-x3)*(y1-y3);
p3 = (x1-x) *(y2-y) -(x2-x) *(y1-y) ;
Then the point (x,y) lies inside or on the triangle if:
sign(c1)*sign(p1) >= 0 & sign(c2)*sign(p2) >= 0 & sign(c3)*sign(p3) >= 0
  2 commentaires
Roger Stafford
Roger Stafford le 27 Fév 2016
Modifié(e) : Roger Stafford le 27 Fév 2016
Two points.
1) My apologies! I made the computations more complicated than they need be. The quantities c1, c2, and c3 are all identically equal, so you need only calculate one of them. They are each twice the signed area of the (straight-lined) triangle. with the sign determined by whether (x1,y1), (x2,y2), (x3,y3) are in counterclockwise or clockwise order around the triangle.
2) In answer to your question of triangles in three-dimensional space, that is a somewhat different situation. Your arbitrary point (x,y,z) has to be shown to lie in the same plane as that of the triangle, if that is what you mean by "belongs to", in addition to satisfying three inequalities. Do you want me to show how this is to be determined?

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