Explicitly numbered string?

13 vues (au cours des 30 derniers jours)
nilsotto
nilsotto le 28 Fév 2016
Commenté : nilsotto le 28 Fév 2016
Hi,
How do I explicitly define a string with numbering? Look at the example below. Suppose "numbers" are unknown and I want to name the figures Q1, Q2 etc.
numbers=3;
fname={'Q1' 'Q2' 'Q3'};
for i=1:numbers
if i==1
x = -2*pi:0.01:2*pi;
elseif i==2
x = -3*pi:0.01:3*pi;
else
x = -4*pi:0.01:4*pi;
end
y = sin(x);
h=figure
plot(x,y);
print(h,'-dpng',fname{1,i});
end

Réponses (2)

Guillaume
Guillaume le 28 Fév 2016
My recommendation is to use sprintf which lets you compose any arbitrary string that you want.
fnames = cell(1, numbers);
for i = 1:numbers
fname{i} = sprintf('Q%d', i);
end
Or as a one-liner:
fnames = cellfun(@(n) sprintf('Q%d', n), 1:numbers, 'UniformOutput', false);
Note that the format string of sprintf is very flexible. If you had more than 10 numbers and wanted to generate: Q01, Q02, ..., Q10, etc.:
sprintf('Q%02d', i)
  2 commentaires
Jan
Jan le 28 Fév 2016
Unfortunately undocumented yet:
fnames = sprintfc('Q%d', 1:numbers)
nilsotto
nilsotto le 28 Fév 2016
Many thanks guys!

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Azzi Abdelmalek
Azzi Abdelmalek le 28 Fév 2016
numbers=3;
fname=genvarname(repmat({'Q'},1,numbers),'Q')
for ii=1:numbers
x = -(ii+1)*pi:0.01:(ii+1)*pi;
y = sin(x);
h=figure
plot(x,y);
print(h,'-dpng',fname{ii});
end
  1 commentaire
Guillaume
Guillaume le 28 Fév 2016
While genvarname would work in this case, it's not for generating abritrary strings, only valid variable names. The set of valid filenames is much greater than the set of valid variable names.

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