I have a piece of code that works without the .* and another that doesn't - can't work out why. This is the one that works
close all
clear all
fo = 4; %Frequency of the sine wave
Fs = 100; %Sampling rate
Ts = 1/Fs; %Sampling time interval
t = 0:Ts:1-Ts;
n = length(t); %Number of samples
x = 2*sin(2*pi*fo*t);
[XfreqD,freqRng] = positiveFFT(x,Fs);
stem(freqRng,abs(XfreqD));
Also, the function that one uses is here -
function[X,freq]=positiveFFT(x,Fs)
N=length(x);
k=0:N-1;
T=N/Fs;
freq=k/T; %Create the frequency range
X=fft(x)/N; %normalise the data
cutOff = ceil(N/2);
X = X(1:cutOff);
freq = freq(1:cutOff);
Then my code - the one that doesn't work is here. It's asking or .^ etc.
close all; clear all
t0=0.05;w0=600*pi;q=5;
%t=linspace(-0.1,0.1,fs);
fs = 100; %Sampling rate
Ts = 1/fs; %Sampling time interval
t = 0:Ts:1-Ts;
n = length(t); %Number of samples
x=exp(-(t/t0)^2)*cos(w0*(1-q*t)*t);
[XfreqD,freqRng] = positiveFFT(x,fs);
stem(freqRng,abs(XfreqD));
This version works - but I have no idea whether it's right or not. Is there a good way of checking?
close all; clear all t0=0.05;w0=600*pi;q=5; %t=linspace(-0.1,0.1,Fs); Fs = 100; %Sampling rate Ts = 1/Fs; %Sampling time interval t = 0:Ts:1-Ts; n = length(t); %Number of samples x=exp(-(t/t0).^2).*cos(w0*(1-q.*t).*t); [XfreqD,freqRng] = positiveFFT(x,Fs); stem(freqRng,abs(XfreqD));

3 commentaires

Jan
Jan le 26 Jan 2012
Please post a copy of the error message instead of the short "does not work". If Matlab suggests ".^", what did happend when you follow this advice?
I have a piece of code that works without the .* and another that doesn't - can't work out why. This is the one that works
close all
clear all
fo = 4; %Frequency of the sine wave
Fs = 100; %Sampling rate
Ts = 1/Fs; %Sampling time interval
t = 0:Ts:1-Ts;
n = length(t); %Number of samples
x = 2*sin(2*pi*fo*t);
[XfreqD,freqRng] = positiveFFT(x,Fs);
stem(freqRng,abs(XfreqD));
Also, the function that one uses is here -
function[X,freq]=positiveFFT(x,Fs)
N=length(x);
k=0:N-1;
T=N/Fs;
freq=k/T; %Create the frequency range
X=fft(x)/N; %normalise the data
cutOff = ceil(N/2);
X = X(1:cutOff);
freq = freq(1:cutOff);
Then my code - the one that doesn't work is here. It's asking or .^ etc.
close all; clear all
t0=0.05;w0=600*pi;q=5;
%t=linspace(-0.1,0.1,fs);
fs = 100; %Sampling rate
Ts = 1/fs; %Sampling time interval
t = 0:Ts:1-Ts;
n = length(t); %Number of samples
x=exp(-(t/t0)^2)*cos(w0*(1-q*t)*t);
[XfreqD,freqRng] = positiveFFT(x,fs);
stem(freqRng,abs(XfreqD));
This version works - but I have no idea whether it's right or not. Is there a good way of checking?
close all; clear all t0=0.05;w0=600*pi;q=5; %t=linspace(-0.1,0.1,Fs); Fs = 100; %Sampling rate Ts = 1/Fs; %Sampling time interval t = 0:Ts:1-Ts; n = length(t); %Number of samples x=exp(-(t/t0).^2).*cos(w0*(1-q.*t).*t); [XfreqD,freqRng] = positiveFFT(x,Fs); stem(freqRng,abs(XfreqD));
Helder Pinheiro
Helder Pinheiro le 26 Juin 2022
Modifié(e) : Helder Pinheiro le 26 Juin 2022

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 Réponse acceptée

Wayne King
Wayne King le 26 Jan 2012

0 votes

Hi Tom, I don't think you need the dot multiplication on q, just
x=exp(-(t/t0).^2).*cos(w0*(1-q*t).*t);
On whether it's right or not, it's not readily apparent to me what you're trying to do with (cos(w0*(1-q*t).*t)

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