cant find problem in my LU decomposition code

4 vues (au cours des 30 derniers jours)
hosein khalili
hosein khalili le 6 Mar 2016
Réponse apportée : Naga le 10 Avr 2025
i wrote this code to determine my l and u for the given matrix,but when i calculate l*u some arrays in its last column isn't the same as given matrix,it has messed up my mind...i appreciate your helps to make my code work.
if true
% clear
clc
a=[0 3 -4 2;2 6 4 -3;-1 -1 2 3;3 0 0 -5];
c=[26;9;7;-19];
n=length(a);
for k=1:n;
pivot=k;
big=abs(a(k,k));
for i=(k+1):n;
if a(i,k)>big;
big=a(i,k);
pivot=i;
end
end
if pivot~=k;
a([pivot,k],:)=a([k,pivot],:);
end
end
for i=1:n;
l(i,1)=a(i,1);
end
for i=1:n;
u(i,i)=1;
end
for j=2:n;
u(1,j)=a(1,j)/l(1,1);
end
for j=2:(n-1);
for i=j:n;
sum=a(i,j);
for k=1:(j-1);
sum=sum-l(i,k)*u(k,j);
end
l(i,j)=sum;
end
for k=(j+1):n;
sum1=a(j,k);
for i=1:(j-1);
sum1=sum1-l(j,i)*a(i,k);
end
u(j,k)=sum1/l(j,j);
end
end
for j=n;
sum2=a(j,j);
for k=1:(n-1);
sum2=sum2-l(j,k)*a(k,j);
end
l(j,j)=sum2;
end

Réponses (1)

Naga
Naga le 10 Avr 2025
Hello Hosein,
There are a couple of issues in your code that might cause incorrect results. You are checking 'a(i,k) > big', but you should be checking 'abs(a(i,k)) > big' for partial pivoting. Additionally, in the logic for computing (L) and (U), the computation of (U) should use the updated values of (L).
Here's a revised version of your code:
a = [0 3 -4 2; 2 6 4 -3; -1 -1 2 3; 3 0 0 -5];
n = length(a);
% Pivoting
for k = 1:n
pivot = k;
big = abs(a(k,k));
for i = (k+1):n
if abs(a(i,k)) > big
big = abs(a(i,k));
pivot = i;
end
end
if pivot ~= k
a([pivot,k],:) = a([k,pivot],:);
end
end
% LU Decomposition
for i = 1:n
L(i,i) = 1; % Diagonal of L is 1
for j = i:n
sum = 0;
for k = 1:(i-1)
sum = sum + L(i,k) * U(k,j);
end
U(i,j) = a(i,j) - sum;
end
for j = (i+1):n
sum = 0;
for k = 1:(i-1)
sum = sum + L(j,k) * U(k,i);
end
L(j,i) = (a(j,i) - sum) / U(i,i);
end
end

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