How can i find deleted rows from matrix??

 x0 = [2     3     2     2     2;
     2     3     2     2     2;
     2     4     1     2     2;
     2     4     1     2     2;
     2     3     2     2     2;
     2     3     2     2     2];

 x0(any(x0<2,2),:) = [];

 x0 = [2     3     2     2     2;
     2     3     2     2     2;
     2     3     2     2     2;
     2     3     2     2     2];

I want to see deleted row separately i.e

     2     4     1     2     2;
     2     4     1     2     2;

I want to know index of x0 which deleted.

[Stephen23]

Question is continued here:

http://www.mathworks.com/matlabcentral/answers/272130-is-it-possible-to-find-corresponding-row-from-other-matrix-s-row

Answer 1

[KSSV]

use k = x0(any(x0<2,2),:) ;

k will be your matrix which you are going to delete.

[KSSV]

If you want to know the indices, I would do the following:

x0(any(x0<2,2),:) = NaN; % Replace with NaN

pos = find(isnan(x0)) ; % Get the position of NaN's

[i,j] = ind2sub(size(x0),pos) ; % Get the sub indices

[Triveni]

can you tell me for

 x00 =[ -45     0    15    45    90;
   -45     0    15    45    90;
   -45     0    15    45    90;
   -45     0    15    45    90;
   -45     0    15    45    90;
   -45     0    15    45    90];

eliminate same rows correspond to x0.

I'm very thankful to you for your response.

[Stephen23]

Save the index and use it:

>> idx = any(x0<2,2);
>> xdel = x0(idx,:)
xdel =

     2   4   1   2   2
     2   4   1   2   2

>> xnew = x0(~idx,:)
xnew =

     2   3   2   2   2
     2   3   2   2   2
     2   3   2   2   2
     2   3   2   2   2

[Stephen23]

I already answered this in your other question.