Function within an integral

Hi,

How can I solve an Integral which looks like:

f(z) = e^A(z)*ln(z), where as A(z) = -z^2

I tried with this code:

fun = @(x) exp(A).*log(x).^2;

A = test_test(x);

q = integral(fun,0,Inf);

function A = test_test(x)

A= -x^2;

end

what am I doing wrong???? PLEASE HELP!!!!!

thanks a lot!!!

Answer 1

[Star Strider]

This works for me:

test_test = @(x) -x.^2;
fun = @(x) exp(test_test(x)).*log(x).^2;
q = integral(fun,0,Inf)

q =
       1.9475

You have to call your function as ‘test_test(x)’ inside ‘fun’, not as ‘A’. (I created an anonymous function for of ‘test_test(x)’ for convenience. If you are using it as a function file, it would work the same way in ‘fun’.)

[beginner]

Thank you soooo much!!!! you are a genius!!!! <3

[Star Strider]

My pleasure!

Thank you!

If my Answer solved your problem, please Accept it!