How can I plus (append) string in each loop?
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Yen Hai
le 12 Mar 2016
Commenté : Image Analyst
le 13 Mar 2016
I have:
person=[1,2];
for i=1:length(person)
if (person(i))== 1
str=sprintf('Person A');
elseif (output(i))==2
str=sprintf('Person B');
elseif (output(i))==3
str=sprintf('Person C');
elseif (output(i))==4
str=sprintf(' Person D');
elseif (output(i))==5
str=sprintf('Person E');
else
str=sprintf('System can not detect!');
end
end
%How can I plus result in each loop, like this:
%str='Person A Person B'
How can I plus result in each loop, like this:
str='Person A Person B'
Thank for your help!
0 commentaires
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Image Analyst
le 12 Mar 2016
Here's another one of many ways. Not necessarily the best, but along the lines of what you started with. (Is this homework?)
person=[1, 2];
finalString = ''; % Initialize
for i=1:length(person)
if (person(i))== 1
str=sprintf('Person A');
elseif (person(i))==2
str=sprintf('Person B');
elseif (person(i))==3
str=sprintf('Person C');
elseif (person(i))==4
str=sprintf('Person D');
elseif (person(i))==5
str=sprintf('Person E');
else
str=sprintf('System can not detect!');
end
finalString = [finalString, ' ', str]; % Append this string.
end
fprintf('The final string = %s\n', finalString);
2 commentaires
Image Analyst
le 13 Mar 2016
Sure, just ask, but remember to attach your images and explain the larger context of what you want.
Plus de réponses (1)
dpb
le 12 Mar 2016
Modifié(e) : dpb
le 12 Mar 2016
I presume output is a typo intending person. But you don't need a loop nor any logical tests at all...
>> people=['A':'Z']; % define population of names from which to pick
>> persons=1:3:8; % chose some arbitrarily
>> sprintf('Person %2c ',people(person))
ans =
Person A Person D Person G
>>
BTW, if don't want the trailing blank or it's a bother, simply wrap with
strtrim(sprintf('Person %2c ',people(person)))
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