Effacer les filtres
Effacer les filtres

array length is not what I've set...

2 vues (au cours des 30 derniers jours)
beginner le 23 Mar 2016
Modifié(e) : Jos (10584) le 23 Mar 2016
This is my code, it works just fine, just I dont understand why my array Hopt_new is generating more arrays than I set.
X = 0:0.1:3;
Hopt_new = zeros([1 90]);
h0_new = 0;
for j = 90:1:179
theta = j*pi/180;
handle = @(h0) test2fun(h0, theta, Bo,X);
Hopt_new(j)=fsolve(handle, h0_new);
h0_new = Hopt_new(j);
Why does Hopt_new have length of 179 instead of 90, which I set before the for loop? Is this because j goes until 179? I mean j actually is a "vector" with length of 90. I just dont get it.
Thanks a lot.
  1 commentaire
Jos (10584)
Jos (10584) le 23 Mar 2016
Yes, take a look at this code, and then see my answer:
A = [1 2 3]
A(6) = 99

Connectez-vous pour commenter.

Réponse acceptée

random09983492 le 23 Mar 2016
The first time the loop executes it sets Hopt_new(90).
The second time it sets Hopt_new(91).
If you want to start at the first index of Hopt_new, assign Hopt_new(j-89) rather than just Hopt_new(j).

Plus de réponses (1)

Jos (10584)
Jos (10584) le 23 Mar 2016
Modifié(e) : Jos (10584) le 23 Mar 2016
In your code, the variable j has two roles:
  1. an index into Hopt
  2. a value that is used for calculation (angle?)
Your best option is to disentangle these using two variables:
Bo = 1;
X = 0:0.1:3;
Hopt_new = zeros([1 90]);
h0_new = 0;
Angle = 90:1:179 ;
for j2 = 1:numel(Angle)
% loop over all angles
theta = Angle(j2) * pi/180;
handle = @(h0) test2fun(h0, theta, Bo, X);
Hopt_new(j2) = fsolve(handle, h0_new);
h0_new = Hopt_new(j2);


En savoir plus sur NaNs dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by