array length is not what I've set...
Afficher commentaires plus anciens
Hi,
This is my code, it works just fine, just I dont understand why my array Hopt_new is generating more arrays than I set.
Bo=1;
X = 0:0.1:3;
Hopt_new = zeros([1 90]);
h0_new = 0;
for j = 90:1:179
theta = j*pi/180;
handle = @(h0) test2fun(h0, theta, Bo,X);
Hopt_new(j)=fsolve(handle, h0_new);
h0_new = Hopt_new(j);
end
Why does Hopt_new have length of 179 instead of 90, which I set before the for loop? Is this because j goes until 179? I mean j actually is a "vector" with length of 90. I just dont get it.
Thanks a lot.
1 commentaire
Jos (10584)
le 23 Mar 2016
Yes, take a look at this code, and then see my answer:
A = [1 2 3]
A(6) = 99
Réponse acceptée
Plus de réponses (1)
Jos (10584)
le 23 Mar 2016
Modifié(e) : Jos (10584)
le 23 Mar 2016
In your code, the variable j has two roles:
- an index into Hopt
- a value that is used for calculation (angle?)
Your best option is to disentangle these using two variables:
Bo = 1;
X = 0:0.1:3;
Hopt_new = zeros([1 90]);
h0_new = 0;
Angle = 90:1:179 ;
for j2 = 1:numel(Angle)
% loop over all angles
theta = Angle(j2) * pi/180;
handle = @(h0) test2fun(h0, theta, Bo, X);
Hopt_new(j2) = fsolve(handle, h0_new);
h0_new = Hopt_new(j2);
end
Catégories
En savoir plus sur Resizing and Reshaping Matrices dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!