How to store vectors with different size in a loop ?

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Ole
Ole le 23 Mar 2016
Commenté : dpb le 15 Avr 2019
How to store vectors with different size and how to access them. M(k) found_roots
F = @(t) cos(t)*exp(-t);
A = @(s) arrayfun(@(s)-integral(F,-10,s),s);
Z = @(t1,t2) -integral(A,t1,t2);
interval = [-5, 5];
N = 100;
start_pts = linspace(interval(1),interval(2),N);
found_roots = [];
for k = 1:10
t2 = k;
for i=1:numel(start_pts)-1
try
found_roots(end+1) = fzero(@(t1)Z(t1,t2),[start_pts(i),start_pts(i+1)]);
end
% i
end
M(k) = found_roots % vector of different length
k
end
  2 commentaires
Benjamin
Benjamin le 15 Avr 2019
But in every loop, if the size of the matrix (output here) changes Matlab gives error of different matrix sizes. Is there anysolution for that.
FYI: my Matlab code generates a matrix of [A] = n*2 and in every loop (for i = 1:10) n changes. I would like to store all A results in another B matrix.
dpb
dpb le 15 Avr 2019
That's what the Answer shows...use cell array instead of "regular" array...the difference is "the curlies" the {} around the subscript, not ()

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dpb
dpb le 23 Mar 2016
Use cell array instead; the curly brackets...
M{k} = found_roots;
  2 commentaires
Ole
Ole le 25 Mar 2016
Modifié(e) : Ole le 25 Mar 2016
Thanks This works but now how to plot them .
dpb
dpb le 25 Mar 2016
"them" can be plotted, sure, but against what?

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