Numerical integration with a singularity at the upper limit

11 vues (au cours des 30 derniers jours)
Linas Tarasonis
Linas Tarasonis le 30 Mar 2016
Commenté : Torsten le 6 Avr 2016
How can I numerically integrate a function with a singularity at the upper limit? The 'integral' function is not smooth to changes in the lower limit. Here is a code with my function and a plot that illustrates the instability:
n=20;
h1=@(x) x.^(1/2+n).*(1-x).^(1/2-n);
inth1=@(p) integral(h1,p,0.99);
fplot(inth1,[0.5,0.55])
quadgk does not solve the problem.

Réponses (2)

John D'Errico
John D'Errico le 30 Mar 2016
No matter what numerical methods scheme one chooses to solve this problem, you can always choose a sufficiently large value of n that makes it unstable. NO numerical method will survive your test, IF you are willing to make your function arbitrarily nasty.
Anyway, there is not in fact a singularity at the limits of integration here, but beyond those limits. The singularities are at x=0 and x=1, whereas you have chosen [p,0.99] as the limits of integration. This is a completely different problem than one with a singularity.
If you insist on solving such arbitrarily nearly singular problems, you will probably need to work in a higher precision arithmetic than double precision. So I'd start by looking at the symbolic toolbox.
  1 commentaire
Linas Tarasonis
Linas Tarasonis le 6 Avr 2016
Thank you, John, for your answer. The symbolic math toolbox works well if n is not too large indeed.

Connectez-vous pour commenter.


Torsten
Torsten le 30 Mar 2016
Your integral only exists for n < 3/2 (if the lower x-limit is greater 0).
Best wishes
Torsten.
  2 commentaires
Linas Tarasonis
Linas Tarasonis le 6 Avr 2016
Thank you for your answer, Torsten. This is why the upper limit is 0.99 instead of 1.
Torsten
Torsten le 6 Avr 2016
0.99 is somewhat arbitrary if the integral does not exist, isn't it ?
Best wishes
Torsten.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Numerical Integration and Differentiation dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by