Roots of a function
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I have two equations:
y1 = 2sinx1;
y2 = 2cos^2(x1) + 3sin(2x2+3);
here y1 = 0 while y2 = 1.
Can anyone please tell me which approach would be the best to find out the values of x1 and x2.
Thank you.
1 commentaire
Torsten
le 30 Mar 2016
x1=0
x2=(asin(-1/3)-3)/2
Best wishes
Torsten.
Réponse acceptée
Plus de réponses (1)
Vlad Miloserdov
le 30 Mar 2016
if you still need this
A=solve('0 = 2*sin(x1)','1 = 2*cos(x1)^2 + 3*sin(2*x2+3)','x1','x2');
% first ans
A.x1(1)
A.x2(1)
% second ans
A.x1(2)
A.x2(2)
5 commentaires
Muhammad Umar Farooq
le 31 Mar 2016
Torsten
le 31 Mar 2016
You have two equations - thus you will need MATLAB's "fsolve".
Best wishes
Torsten.
Muhammad Umar Farooq
le 31 Mar 2016
Torsten
le 31 Mar 2016
Please show your code.
Best wishes
Torsten.
Muhammad Umar Farooq
le 31 Mar 2016
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