function to solve a binary matrix?

If i have a binary matrix (NxM)

A =[0 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1
    0 1 1 0 1 1 1 1 1 1 1 1 0 1 0 1
    1 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1
    0 1 0 1 1 1 0 0 0 0 0 1 1 1 1 1
    0 1 1 1 1 0 1 0 0 1 1 1 1 1 0 1
    0 0 1 1 0 1 1 0 1 1 1 0 1 0 0 1
    0 1 0 0 1 0 1 1 1 1 0 1 1 1 0 1
    0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0
    1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
    0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 1];

I need a function to calculate number of 1 and in each row and put it in a new matrix like this

B = [ 1 1 1 1 1 1 1
      2 8 1 1
      2 1 5
      1 3 5
      4 1 5 1
      2 2 3 1 1
      1 1 4 3 1
      13
      15 
      5 1 ]

And a third matrix for a column like this

C = [ 1 4 2 4 2 1 2 1 2 1 2 4 1 4 2 7
      1 3 2 2 2 1 6 4 5 6 2 3 7 3 1 2
          2   3 1         2
              3                       ]

• Note when the counter see zero then the counter will be stop and start again for example [0 1 1 0 1 1 1 1 1 ] then the solution will be [2 5]

Answer 1

[Azzi Abdelmalek]

A =[0 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1
  0 1 1 0 1 1 1 1 1 1 1 1 0 1 0 1
  1 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1
  0 1 0 1 1 1 0 0 0 0 0 1 1 1 1 1
  0 1 1 1 1 0 1 0 0 1 1 1 1 1 0 1
  0 0 1 1 0 1 1 0 1 1 1 0 1 0 0 1
  0 1 0 0 1 0 1 1 1 1 0 1 1 1 0 1
  0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0
  1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
  0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 1]
[n,m]=size(A);
B=(m+repmat(1:m,n,1)-A.*cumsum(A,2)).*A;
for k=1:n
  a=B(k,B(k,:)~=0);
  [~,~,kk]=unique(a);
  row1{k,1}=accumarray(kk,1);
end
celldisp(row1)

[Azzi Abdelmalek]

For the column, you can use the same code, just transpose your matrix

C=(n+repmat(1:n,m,1)-A'.*cumsum(A',2)).*A'
for k=1:m
  a=C(k,C(k,:)~=0);
  [~,~,kk]=unique(a);
  col1{k,1}=accumarray(kk,1);
end
celldisp(col1)

[Firas Al-Kharabsheh]

can you give me your email ???

[Firas Al-Kharabsheh]

Thank you

[Firas Al-Kharabsheh]

can you help me on this question http://www.mathworks.com/matlabcentral/answers/276558-function-matrix-used-summation