How to sort a matrix using loops?

I need to sort a matrix from least to greatest without the sort function. It needs to be done in nested loops. For example, I need to take the matrix [9 5;7 4;8 6] and sort it into [4 5;6 7;8 9].

1 commentaire

See this site for a variety of possible algorithms you might use:
https://en.wikipedia.org/wiki/Sorting_algorithm

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Réponses (1)

John BG
John BG le 17 Avr 2016
Modifié(e) : John BG le 17 Avr 2016

0 votes

Michael
1 for loop is enough
A=randi([-10 10],5,6) % generate input
B=A(:)' % reshape A into straight line
L=length(B)
C=[]
for k=1:L
v=find(B==max(B)) % in case repeated values
C=[C B(v(1))]
B(v(1))=[]
end
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thanks in advance
John

2 commentaires

Jan
Jan le 17 Avr 2016
The missing pre-allocation is a bad programming style.
John BG
John BG le 17 Avr 2016
Modifié(e) : John BG le 24 Avr 2016
Actually, you are right, there are other ways to build the variable collecting the result, some good habits die hard, like declaring variables before using them.
The 'bad' you mention, why? Because it's going to size some more bytes disk?

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