Replacing a for loop with logical indexing

If someone could help me out with this simple problem, I would really appreciate it. I'm still trying to wrap my head around indexing. I have a 5x5 array [A], and I would like have a logical 1x5 array B, where B indicates the columns of A that have 3 or more NaN values. So far I've been able to make a for loop, but I would like to simplify this if possible to a logical index.

A = [1,2,3,4,5;2,3,4,5,6;NaN,NaN,NaN,NaN,NaN;NaN,NaN,NaN,4,NaN;NaN,NaN,7,8,NaN];

B = zeros(1,5);

for i = 1:5
    if numel(find(isnan(A(:,i)))) > 2
        B(i) = 1;
    end
end

 (output) B = [1,1,0,0,1]

Thank you for your time.

Answer 1

[Azzi Abdelmalek]

out=sum(isnan(A))>=3

[Tyler]

Thank you!

Answer 2

[Jon]

B = sum(isnan(A))>2;

[Tyler]

Thanks!