# Replacing a for loop with logical indexing

12 vues (au cours des 30 derniers jours)
Tyler le 28 Avr 2016
Commenté : Tyler le 28 Avr 2016
If someone could help me out with this simple problem, I would really appreciate it. I'm still trying to wrap my head around indexing. I have a 5x5 array [A], and I would like have a logical 1x5 array B, where B indicates the columns of A that have 3 or more NaN values. So far I've been able to make a for loop, but I would like to simplify this if possible to a logical index.
A = [1,2,3,4,5;2,3,4,5,6;NaN,NaN,NaN,NaN,NaN;NaN,NaN,NaN,4,NaN;NaN,NaN,7,8,NaN];
B = zeros(1,5);
for i = 1:5
if numel(find(isnan(A(:,i)))) > 2
B(i) = 1;
end
end
(output) B = [1,1,0,0,1]
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### Réponse acceptée

Azzi Abdelmalek le 28 Avr 2016
Modifié(e) : Azzi Abdelmalek le 28 Avr 2016
out=sum(isnan(A))>=3
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Tyler le 28 Avr 2016
Thank you!

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### Plus de réponses (1)

Jon le 28 Avr 2016
B = sum(isnan(A))>2;
##### 1 commentaireAfficher AucuneMasquer Aucune
Tyler le 28 Avr 2016
Thanks!

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