If statement with 2 commands

I have a 1 x 3 matrix (DMS).

Values are [26, 50, 60]

Code is:

if DMS(1,3) == 60
     DMS (1,2) = DMS (1,2) + 1 & DMS(1,3) == 0
 else 
  end

The purpose is to roll over (add 1) to the second elements value and set the third elements value to 0.

During runtime I am getting a value of [26, 0, 60].

What is wrong with my coding of the if statement for the desired values to be returned?

Answer 1

[Roger Stafford]

Your code should be:

   if DMS(1,3) == 60
     DMS (1,2) = DMS (1,2) + 1;
     DMS(1,3) = 0;
   end

The '&' operator is not to be used as "do this AND do this". It functions only as a logical operator such as (x<10)&(x>3) meaning that it is true if x is less than ten and greater than 3.

Also the '==' is not an assignment symbol. It is another logical operator. The expression x==5 is true whenever x is exactly equal to 5.

[Stephen23]

Justin's "Answer" moved here:

Thanks Roger,

I should also use = and not == for 0 value.

That was fast and easy.

Thanks again.

Answer 2

[Elias Gule]

Ok, I think I see two problems in your if statement. 1). == is not an assignment operation, but rather a comparative one. So

DMS(1,3) == 0

checks if the value at row 1 column 3 of the DMS vector/matrix is 0; in your case it checks whether 60 is equal to 0, which returns 0 (a logical false is Matlab). 2). The & operator is a logical and. So

DMS (1,2) = DMS (1,2) + 1 & DMS(1,3) == 0

first calculates the value of DMS(1,2) + 1 => 51, then performs the operation described in 1) above, resulting 51 & 0, which returns 0.

To solve your problem: replace the ampersand ("&") with a semicolon (";"), and the "==" with "=", such that the statement will now be,

DMS (1,2) = DMS (1,2) + 1; DMS(1,3) = 0;