How to avoid that loop

k(1) = 1;

for i=2:size(k)
  k(i) = k(i-1)*v(i)
end

v(i) is a scalar and it's different on every iteration How could I do that without using a loop?

[the cyclist]

As written, this loop will never be executed, because size(k) is 1, and

for i = 2:1
  <stuff>
end

will have zero iterations.

Some coding mistake? Maybe you meant length(v)?

[Alberto Menichetti]

I'm sorry you're right

k = ones(size(v), 1);

Answer 1

[the cyclist]

If my speculation about what you meant it correct, then

k = cumprod(v)/v(1)

[Alberto Menichetti]

I think I didn't explain my problem very well:

k(1) = 1

I want

k(i) = k(i-1)*v(i)

for every i>1

[Steven Lord]

No, we understand you. Another approach that doesn't involve division:

v = randperm(8) % Sample data for demonstration purposes
k = cumprod([1 v(2:end)])