Effacer les filtres
Effacer les filtres

How do I show that my matrix is unitary?

14 vues (au cours des 30 derniers jours)
Bryan Acer
Bryan Acer le 9 Mai 2016
I have a matrix H with complex values in it and and set U = e^(iH). My code to verify that U is a unitary matrix doesn't prove that U' == U^-1 which holds true for unitary matrices. What am I doing wrong? Thank you!
H = [2 5-i 2; 5+i 4 i; 2 -i 0]
U = exp(i * H)
UConjTrans = U'
UInverse = inv(U)
  3 commentaires
Bryan Acer
Bryan Acer le 9 Mai 2016
Modifié(e) : Bryan Acer le 9 Mai 2016
The wording of the problem implies that H is hermitian and that U must therefore be a unitary matrix given by U = e^(i*H)
"show that H is hermitian." "Show U is unitary. (Recall a unitary matrix means U† = U−1)"
Roger Stafford
Roger Stafford le 9 Mai 2016
It is obviously true that H is Hermitian symmetric, but it does not follow that exp(i*H) is unitary, as you yourself have shown.
Note: The set of eigenvectors obtained by [V,D] = eig(H) can constitute a unitary matrix in such a case if properly normalized.

Connectez-vous pour commenter.

Réponses (1)

Roger Stafford
Roger Stafford le 9 Mai 2016
Modifié(e) : Roger Stafford le 9 Mai 2016
The problem lies in your interpretation of the expression e^(i*H). It is NOT the same as exp(i*H). What is called for here is the matrix power, not element-wise power, of e. The two operations are distinctly different. Do this:
e = exp(1);
U = e^(i*H);
You will see that, subject to tiny rounding error differences, the inverse of U is equal to its conjugate transpose.
See:
http://www.mathworks.com/help/matlab/ref/mpower.html

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by