store data from matrix rowwise in indexed structure

1 vue (au cours des 30 derniers jours)
Doreen
Doreen le 10 Mai 2016
Commenté : Andrei Bobrov le 10 Mai 2016
Hello everyone, I have a structure 'Sample', which contains many objects (over 1000) with the same attributes. For example sample specific data is stored as a 1x2090 vector under Sample([]).YData. If I want to extract the 'YData' of sample 1 to 151 and store it in a matrix, I simply write
Select = 1:151; YData = vertcat(Sample(Select).YData);
Now I want to write selected data back to structure... Each row of a matrix should be written to the 'YData' of the corresponding sample.
Sample(Select).YData = Matrix;
doesn't work. Is there a way to implement this task in such a simple way or will only a for-loop do this job? Thanks

Réponse acceptée

Guillaume
Guillaume le 10 Mai 2016
Modifié(e) : Guillaume le 10 Mai 2016
To create your matrix in the first place you went through two steps:
  1. Created a comma separated list out of your structure (simply by writing Sample(Select).YData)
  2. Concatenated together all the elements of the list into one matrix with vertcat
To do the inverse you have to reverse these steps
  1. Split the matrix into rows
  2. deal these rows to the structure
Unfortunately, it can't be done as a one-liner, you have to use a temporary variable
rows = num2cell(Matrix, 2); %split matrix into rows
[Sample(Select).YData] = rows{:}; %distribute rows into structure
  3 commentaires
Doreen
Doreen le 10 Mai 2016
Great :-) Many thanks!
Andrei Bobrov
Andrei Bobrov le 10 Mai 2016
But working in Octave:
Sample(Select) = cell2struct(num2cell(Matrix,2),{'YData'},2);

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Shifting and Sorting Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by