Effacer les filtres
Effacer les filtres

how to name a figure using a variable name

8 vues (au cours des 30 derniers jours)
Johannes Deelstra
Johannes Deelstra le 14 Mai 2016
Commenté : Image Analyst le 23 Mai 2016
I have a figure and want to save this as a tiff or jpeg I have changed a date into variable = 'van190392 15' which I want to use in the file name Such that I get as filename;van190392 15.tiff or van190392 15.jpeg I get an error message, it seems not being allowed/possible

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the cyclist
the cyclist le 15 Mai 2016
Modifié(e) : the cyclist le 15 Mai 2016
variable = 'van190392 15';
figure
plot(rand(3,4))
filename = [variable,'.tif'];
print('-dtiff',filename)
  2 commentaires
the cyclist
the cyclist le 22 Mai 2016
Moved Johannes comment from an "answer" to here. He wrote,
"Thanks for the help, functions great"
Image Analyst
Image Analyst le 23 Mai 2016
A related note: To get a figure to have a name you want, instead of like "Figure 1", "Figure 2", etc., you can turn the 'NumberTitle' property 'Off' and set the 'name' property of the figure to a literal string or a string variable:
% Give a name to the title bar/figure.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')

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