I'm tying to limit the length of an equation by doing this.
Al = @(x) 25.5e3+(300*x(1))+(x(1))^2;
Aj = @(x) (tan((2*pi)/9))*((x(1))^2+(100*x(1))+50);
Ak = @(x) (1000*(200*x(1))*(x(1))^2)/(2*tan((2*pi)/9));
func = @(x) x(3)*(47e3-Al+Aj+Ak);
What am I doing wrong?
I've read the guides on function handles etc, but I just cant understand it! I don't think I'm meant to be a programmer but I have to do this unfortunately.
Thanks in advance

 Réponse acceptée

Kevin Holst
Kevin Holst le 8 Fév 2012

0 votes

It looks like this is all that's wrong:
func = @(x) x(3)*(47e3-Al(x)+Aj(x)+Ak(x));
I'm assuming x is a 3 value vector?

1 commentaire

Will
Will le 8 Fév 2012
Correct. Thank you. sorry for the stupid questions!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Interactive Control and Callbacks dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by