How can I read the elements of an array backwards?
143 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Konstantinos
le 18 Mai 2016
Réponse apportée : Johannes Kalliauer
le 19 Avr 2021
I have an array with x = 250000 elements. I want the code to read backwards a part of it:
k = pks3(1):-1:1;
%read data points backwards starting from pks3 and ending at the beginning
So even though I have i = 10 pks3 peak points, I want to create an array k from the first point pks3(1). But, the problem is that in the end I get k = 255997855 elements, in which the pks3 point for example is repeated for several hundreds of times. The rest of the code is this:
k = pks3(1):-1:1;
%read data points backwards starting from pks3 ending to pks3 again.
first = k(k<xfb1); % find all k such that k is smaller than xfb1
if ~isempty(first)
first = first(1); %store the first number which is smaller than xfb1
else
disp('No value of k is smaller than xfb1.')
end
distQ = length(first:pks3(1));
Qstart = locs_RwaveB(1)*distQ; %distance from locs_RwaveB to Qstart point
What am I doing wrong?
Thanks.
0 commentaires
Réponse acceptée
Ahmet Cecen
le 18 Mai 2016
It appears to me that you are trying to do something very simple in a very convoluted way, probably due to programming practices in another language.
If you need to read x in reverse order, assuming x is a column vector simply do:
x = flipud(x); % flips the vector.
And now you can access it in forward order.
6 commentaires
Stephen23
le 18 Mai 2016
The problem is not the end, it is the pks3(1). What value does pks3(1) have?
Plus de réponses (1)
Johannes Kalliauer
le 19 Avr 2021
a horizontal vector can be fliped using fliplr
x=1:4
x=fliplr(x)
0 commentaires
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!