how to delete rows from matrix
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
m. muner
le 24 Mai 2016
Commenté : Anoire BEN JDIDIA
le 17 Oct 2016
hello i have 53*3 matrix but include rows that three column of the row are zeros i want to delete the entire row i tried this but since every delete shift the location of the other rows i had problem with the for loop so what can i do to overcome this
[c u]=size(test_ary); %dimensions
for i=1:c
for b=1:u
if(test_ary(i,1)==(o)));
test_ary(i,:)=[];
end
end
end
0 commentaires
Réponse acceptée
James Tursa
le 24 Mai 2016
Modifié(e) : James Tursa
le 24 Mai 2016
Replace your for-loop with this vectorized code:
x = all(test_ary==0,2); % Which rows are all 0's
test_ary(x,:) = []; % Delete those rows
Plus de réponses (3)
Jos (10584)
le 26 Mai 2016
Using the statement "test_ary(i,:) = []" you will change the size of it, which will cause problems!
tf = all(test_ary==0,2) % true for rows with only 0's
test_ary(tf,:) = [] % remove those rows using logical indexing
Anoire BEN JDIDIA
le 14 Oct 2016
I have a big matrix 599794x2 i want to delete rows which contains values which repeats for exemple if A=[1,1;2,1;3,1;4,1;5,2;6,2;7,2]; i want to have A=[1,1;5,2]
2 commentaires
James Tursa
le 14 Oct 2016
In the future open up a new Question for this rather than piggyback on an existing Question. But I will answer this here this time:
A = A(logical([1;diff(A(:,2))]),:);
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!